Breeding Bunnies
(A modification of Breeding Bunnies from the PBS website for Evolution ©2001 WGBH Educational Foundation and Clear Blue Sky Productions, Inc. All rights reserved.)
In this activity, you will examine natural selection in a small population of wild rabbits. Evolution, on a genetic level, is a change in the frequency of alleles in a population over a period of time. Breeders of rabbits have long been familiar with a variety of genetic traits that affect the survivability of rabbits in the wild, as well as in breeding populations. One such trait is the trait for furless rabbits (naked bunnies). This trait was first discovered in England by W.E. Castle in 1933. The furless rabbit is rarely found in the wild because the cold English winters are a definite selective force against it.
Note: In this lab, the dominant allele for normal fur is represented by F and the recessive allele for no fur is represented by f. Bunnies that inherit two F alleles or one F and one f allele have fur, while bunnies that inherit two f alleles have no fur. The red beans represent the allele for fur (F), and the white beans represent the allele for no fur (f). The container represents the English countryside, where the rabbits randomly mate.
Procedure:
1) Create a table to record the numbers of individuals with each genotype (FF, Ff and ff), the numbers of each allele (F and f), the number of total alleles (F + f), and the gene frequencies for each allele (F and f) for all 10 generations (see below)
2) Label one dish FF for the homozygous dominant genotype, a second dish Ff for the heterozygous genotype, and a third dish ff for the homozygous recessive genotype.
3) Place 50 red beans and 50 white beans into the container
a. Please note that frequencies have been chosen arbitrarily for this activity.
4) Shake up (mate) the rabbits.
5) Without looking at the beans, select two at a time, place them in the appropriate dish, and record the results on the data form next to "Generation 1."
a. For example, if you draw one red and one white bean, place them in the dish labeled Ff and place a mark in the chart under "Number of Ff individuals."
6) Continue drawing pairs of beans, sorting, and recording the results until all beans have been selected and sorted.
a. Please note that the total number of individuals will be half the total number of beans because each rabbit requires two alleles.
7) The ff bunnies are born furless. The cold weather kills them before they reach reproductive age, so they can't pass on their genes. Place the beans from the ff dish aside before beginning the next round.
8) Count the F and f alleles (beans) that were placed in each of the "furred rabbit" dishes in the first round and record the number in the chart in the columns labeled "Number of F Alleles" and "Number of f Alleles."
a. Note: You are counting each bean, but don't count the alleles of the ff bunnies because they are dead.
9) Total the number of F alleles and f alleles for the first generation and record this number in the column labeled "Total Number of Alleles."
10) Place the alleles of the surviving rabbits (which have grown, survived and reached reproductive age) back into the container and mate (shake) them again to get the next generation.
11) Repeat steps five through ten to obtain generations two through ten. If working as a team, make sure everyone in your group has a chance to either select the beans or record the results.
12) Determine the gene frequency of each allele (F and f) for each generation by dividing the number of each allele by the total number of alleles. Express results in decimal form and record this information in the chart columns labeled "Gene Frequency F" and "Gene Frequency f."
a. For example, to find the gene frequency of F for generation 1, divide the number of F alleles for generation 1 by the total number of alleles for generation 1.
b. The sum of the frequency of F and f should equal one for each generation.
13) Give your findings to your teacher to record the class results.
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Generation |
Number of FF individuals |
Number of Ff individuals |
Number of ff individuals |
Number of F alleles |
Number of f alleles |
Total number of alleles |
Gene frequency of F |
Gene frequency of f |
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10 |
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Observations
Conclusions
EXTRA CREDIT: 5pts
Using your data and the Hardy-Weinberg Variables and Equations (see below) to solve the following questions.
Hardy Weinberg Variables and Equations
p=frequency of dominant allele
q= frequency of recessive allele
p + q = 1
p2= frequency of individuals who are homozygous dominant
q2= frequency of individuals who are homozygous recessive
2pq= frequency of individuals who are heterozygous
p2 + 2pq + q2 = 1